ABCD is a square. Its side is equal to 10cm. AMTD is a rectangle. Its shorter side is equal to 3 cm. How many centimetres is the perimeter of the square ABCD larger than that of the rectangle AMTD?
A.14 cm. B. 10 cm. C. 7 cm. D. 6 cm. E. 4 cm
Subscribe to:
Post Comments (Atom)
14
ReplyDeleteA. 14
ReplyDelete40 (10 + 10 + 10 = 10) - 26 (10 + 10 + 3 + 3) = 14
40 - 26 = 14