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Mr. Chin went to a store where he spent one-half of his money and then $14 more. He then went to another store where he spent one-third of his remaining money and then $14 more. He then had no money left. How much did he have when he entered the first store?
In the second store, the last thing he did before going broke was spend $14. Just before that, he had some money but he spent 1/3 of it and was left with $14.
So $14 is 2/3 of what he had when he entered the second store. $14 is double $7. So when he entered the store, he spent $7 and was left with $14. So he had $21 at the entrance of the second store.
In the first store, the last thing he did was spend $14, leaving him with $21 for the second store; that means that after he had spent half his money in the first store, he had $35, so he started out with double that, which must have been $70.
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ReplyDelete23
ReplyDelete70
ReplyDelete70 - (35+14) = 21
21 - (7+14) = 0
(x - x/2-14)*1/3 - 14 =0
ReplyDelete(x/2-14)*1/3 = 14
Answer - 112
Funky Fries I think you missing something
ReplyDelete112 - (56+14) = 42
42 - (14+14) = 28
28 is not 0
70!!!!!!!!!
ReplyDelete1/2x+14+1/3(1/2x-14)+14=x
Solving this without algebra...
ReplyDeleteAt the end of this story, the man is flat broke.
In the second store, the last thing he did before going broke was spend $14. Just before that, he had some money but he spent 1/3 of it and was left with $14.
So $14 is 2/3 of what he had when he entered the second store. $14 is double $7. So when he entered the store, he spent $7 and was left with $14. So he had $21 at the entrance of the second store.
In the first store, the last thing he did was spend $14, leaving him with $21 for the second store; that means that after he had spent half his money in the first store, he had $35, so he started out with double that, which must have been $70.