Figures I, II, III and IV are squares. The circumference of square I is 16m and the circumference of square II is 24m. Find the circumference of square IV.

*A. **56m **B. **60m **C. **64m **D. **72m **E. **80m*

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## Prof. Giray Okten

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64

ReplyDelete(B) 64

ReplyDelete64

ReplyDelete64

ReplyDeleteC-64

ReplyDeleteThe circumference of I is 16; that means the individual sides are 16/4 which is 4.

ReplyDeleteThe circumference of II is 24; that means the sides are 24/4 which is 6. So the sides of III are 10 because 6+4=10.

To find the side of IV, add the side of III and the side of II to get 10+6=16.

Therefore the circumference of IV is 16x4 = 64.

my answer is "c". The strategy i used to get to my answer is simple. First i calculated how long the sides of squares 1 and 2 were. After that I added the one side of each square 1 and 2 to get the side of 3 which equaled 10. Then I added the side from 2 and 3 to get the side of 4 which equaled 16. I Then multiplied 16 by 4 to get the circumference of square 4 and that equaled 64.

ReplyDeleteMy answer is (C), 64 cm

ReplyDeleteThe answer I got was C (64 cm)

ReplyDelete