A workshop in Florida for 2009 Math Kangaroo Competition.
Visit Math Kangaroo webpage for registration and information about the competition: www.mathkangaroo.org
A. 56m B. 60m C. 64m D. 72m E. 80m
The circumference of I is 16; that means the individual sides are 16/4 which is 4. The circumference of II is 24; that means the sides are 24/4 which is 6. So the sides of III are 10 because 6+4=10. To find the side of IV, add the side of III and the side of II to get 10+6=16. Therefore the circumference of IV is 16x4 = 64.
my answer is "c". The strategy i used to get to my answer is simple. First i calculated how long the sides of squares 1 and 2 were. After that I added the one side of each square 1 and 2 to get the side of 3 which equaled 10. Then I added the side from 2 and 3 to get the side of 4 which equaled 16. I Then multiplied 16 by 4 to get the circumference of square 4 and that equaled 64.
My answer is (C), 64 cm
The answer I got was C (64 cm)